# trick question needs help ASAP !!

• Oct 23rd 2007, 12:04 PM
StephE4kids
trick question needs help ASAP !!
This is a ? my 5th-grader got (so I'm not smarter than a 5th grader!):
"When dividing a 3-digit # by a 1-digit #, for what divisors can you get a remainder of 8? Explain." I'm totally baffled, except to take shots-in-the-dark on a thousand different combos! HELP, PLEASE!!!
• Oct 23rd 2007, 12:34 PM
SnipedYou
I think 9 would be the only possible because it is the only 1 digit number greater than 8. The remainder must be less than the divisor.
• Oct 23rd 2007, 12:42 PM
Jhevon
Quote:

Originally Posted by SnipedYou
I think 9 would be the only possible because it is the only 1 digit number greater than 8. The remainder must be less than the divisor.

indeed. you are correct

you could also have listed all the forms for numbers divisible by 1 digit numbers which have a remainder 8 (there are only 9 or so), you would have found the divisor 9 to be the only appropriate choice. but that's too much work for a 5th grader i suppose
• Oct 23rd 2007, 01:36 PM
StephE4kids