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Hi not sure if this right area but really need help with this
ive not done maths for many years, been given 2 papers to learn. ive been trying for ages to work these out but reallt have no idea,
can someone help me with this 1 and then i will try second on own..
Ive uploaded the paper via PDF file please help me
Re: Hi not sure if this right area but really need help with this
Hi, I'll help you with the Task 5.
from there on we'll replace every y with (18-x)
+4(18-x)=-60\\x^2 -2x*18-2x*(-x)+4*18+4*(-x)\\ = x^2 -36x +2x^2+72-4x\\=3x^2-40x+72 = -60)
Then
From there on you can use the quadratic formula
end up with 
as for the graph part, Draw the 2 fonction they'll meet in these value of X. (*Unless I messed up*)
Re: Hi not sure if this right area but really need help with this
thank you so much for your time and trying to help.. could you possible explain each step and how you do it.. that way i can learn and possible do the other paper myself
thanks again
Re: Hi not sure if this right area but really need help with this
mhm after replacing y, I just added everything together. then I used the quadratic formula.
The quadratic formula is
\sqrt(b^2-4ac)}{2a})
for 
Maybe you could tell me witch part you didn't understand?
Re: Hi not sure if this right area but really need help with this
Quote:
Originally Posted by
Barioth 
mhm after replacing y, I just added everything together. then I used the quadratic formula.
The quadratic formula is
\sqrt(b^2-4ac)}{2a})
for
Maybe you could tell me witch part you didn't understand?
[TEX]\pm[/TEX] gives 
.
Also [TEX] \frac{-b\pm)\sqrt{b^2-4ac}}{2a}[/TEX] gives 
Re: Hi not sure if this right area but really need help with this
