Division Review Problem

**KhanDisciple** · January 15th 2013, 06:01 PM

Hello all, I was doing some review of complex fractions but I am not sure if I did this one right, please let me know if, or where, I went wrong. I also wanted to practice using latex some more. Thanks!
Reduce to lowest terms:

$\frac{y-\frac{1}{y}}{1-\frac{1}{y}}$ = $\frac{\frac{y^2-1}{y}}{\frac{y-1}{y}}$ = $\frac{y^2-1}{y}*\frac{y}{y-1}$ = $\frac{y^3-y}{y^2-y}$

**divans** · January 15th 2013, 06:08 PM

When you flipped the fraction in the denominator, you can cancel both terms out. Try factoring the numerator at this step (a difference of squares):
$\frac{y^2-1}{y}*\frac{y}{y-1}$

**MarkFL** · January 15th 2013, 06:31 PM

I would simply multiply the fraction by $1=\frac{y}{y}$ :

$\frac{y-\frac{1}{y}}{1-\frac{1}{y}}\cdot\frac{y}{y}=\frac{y^2-1}{y-1}=\frac{(y+1)(y-1)}{y-1}=y+1$

**KhanDisciple** · January 15th 2013, 06:47 PM

oh that's right, thanks a lot. I always miss those because at first glance it looks prime.

Thread: Division Review Problem

LinkBack

Thread Tools

Display

Division Review Problem

Re: Division Review Problem

Re: Division Review Problem

Re: Division Review Problem

Similar Math Help Forum Discussions

Differentiating with respect to x^2 and 1/(1-x)... AP review problem

Please Review Mechanics slope problem

Review answer to simplification problem

A problem on the review set

Limits review problem

Search Tags