# Thread: algebara2

1. ## algebara2

hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP

2. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
I really cannot understand what the question is, can you be clearer?

3. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
Although it is easy to trace your question from the given answer, it is better if you present your questions in ways that can be understood by all. You tried, basing from your correct use of parentheses, but the two "square" did not help. I assume you did not know yet that "a^2" is the symbol for "a,squared" or "a, square" or "square of a"
If you like to learn/use LaTex, the "a^2" will appear as the familiar "a, squared" as you would write it on paper.

(-1/3)[(1/6)^2]*[(-1/3)(1/6) -(-1/3)^2]
= (-1/3)(1/36)*[(-1/18) -(1/9)]
= (-1/108)*[(-1 +2(-1))/18]
= (-1/108)*[(-3)/18]
= (-1/108)(-1/6)
= 1/648 ------------------answer.