I'm having a problem with setting the image of a function or interval of a function.
I do understand how to calculate the pre-image.
f(x) = -x^2 - 3
so to calculate the pre-image of the interval (0,1) I simply calculate 0 = -x^2 - 3 and I get minus square root of 3 and square root of 3,
and 1 = -x^2 - 3 and I get minus square root of 2 and square root of 2.
1) how to calculate the image of the function?
2)image of the interval (-1,3)?
3) and why is the pre-image of the interval (3,10) = 0 and (3,4) = ?