Thread: simple graphing in algebra

hi im new here, and i need help in this simple question..
can anyone explain how i can graph this: y = 3/2x + 1
please i would appreciate any input
thanks!

Hi there

It is not entirely clear what you mean; y = (3/2)x + 1 or y = 3/(2x) + 1? These are very different equations

sorry, i meant:
y = (3/2)x + 1

We are given to graph:



This line is in the so-called slope-intercept form , where is the slope and the y-intercept is .

So, plot the y-intercept first...it is (0,1).

Now, since the slope is , from the y-intercept you may move two units to the right and three units up to (2,4) and plot a point there. Now, extend a line through the two points and you will have graphed the equation.

Another method we be to write the equation in the two-intercept form :



Now, we can see we have the two intercepts:



Plot these points and extend a line through them.

very useful.. thanks
im really dumb now i forgot math and i have to get at least 30% in a placement test for college, so im reviewing a lot now