hi im new here, and i need help in this simple question..
can anyone explain how i can graph this: y = 3/2x + 1
please i would appreciate any input
thanks!
We are given to graph:
$\displaystyle y=\frac{3}{2}x+1$
This line is in the so-called slope-intercept form $\displaystyle y=mx+b$, where $\displaystyle m$ is the slope and the y-intercept is $\displaystyle (0,b)$.
So, plot the y-intercept first...it is (0,1).
Now, since the slope is $\displaystyle m=\frac{3}{2}$, from the y-intercept you may move two units to the right and three units up to (2,4) and plot a point there. Now, extend a line through the two points and you will have graphed the equation.
Another method we be to write the equation in the two-intercept form $\displaystyle \frac{x}{a}+\frac{y}{b}=1$:
$\displaystyle \frac{x}{-\frac{2}{3}}+\frac{y}{1}=1$
Now, we can see we have the two intercepts:
$\displaystyle \left(-\frac{2}{3},0 \right),\,(0,1)$
Plot these points and extend a line through them.