hi im new here, and i need help in this simple question..
can anyone explain how i can graph this: y = 3/2x + 1
please i would appreciate any input
We are given to graph:
This line is in the so-called slope-intercept form , where is the slope and the y-intercept is .
So, plot the y-intercept first...it is (0,1).
Now, since the slope is , from the y-intercept you may move two units to the right and three units up to (2,4) and plot a point there. Now, extend a line through the two points and you will have graphed the equation.
Another method we be to write the equation in the two-intercept form :
Now, we can see we have the two intercepts:
Plot these points and extend a line through them.