# simple graphing in algebra

• Jan 9th 2013, 07:42 AM
phyfreak
simple graphing in algebra
hi im new here, and i need help in this simple question..
can anyone explain how i can graph this: y = 3/2x + 1
please i would appreciate any input
thanks!
• Jan 9th 2013, 08:18 AM
kinhew93
Re: simple graphing in algebra
Hi there

It is not entirely clear what you mean; y = (3/2)x + 1 or y = 3/(2x) + 1? These are very different equations :)
• Jan 9th 2013, 10:21 AM
phyfreak
Re: simple graphing in algebra
sorry, i meant:
y = (3/2)x + 1
• Jan 9th 2013, 10:36 AM
MarkFL
Re: simple graphing in algebra
We are given to graph:

$y=\frac{3}{2}x+1$

This line is in the so-called slope-intercept form $y=mx+b$, where $m$ is the slope and the y-intercept is $(0,b)$.

So, plot the y-intercept first...it is (0,1).

Now, since the slope is $m=\frac{3}{2}$, from the y-intercept you may move two units to the right and three units up to (2,4) and plot a point there. Now, extend a line through the two points and you will have graphed the equation.

Another method we be to write the equation in the two-intercept form $\frac{x}{a}+\frac{y}{b}=1$:

$\frac{x}{-\frac{2}{3}}+\frac{y}{1}=1$

Now, we can see we have the two intercepts:

$\left(-\frac{2}{3},0 \right),\,(0,1)$

Plot these points and extend a line through them.
• Jan 9th 2013, 12:08 PM
phyfreak
Re: simple graphing in algebra
very useful.. thanks
im really dumb now i forgot math and i have to get at least 30% in a placement test for college, so im reviewing a lot now