hi im new here, and i need help in this simple question..

can anyone explain how i can graph this: y = 3/2x + 1

please i would appreciate any input

thanks!

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- Jan 9th 2013, 06:42 AMphyfreaksimple graphing in algebra
hi im new here, and i need help in this simple question..

can anyone explain how i can graph this: y = 3/2x + 1

please i would appreciate any input

thanks! - Jan 9th 2013, 07:18 AMkinhew93Re: simple graphing in algebra
Hi there

It is not entirely clear what you mean; y = (3/2)x + 1 or y = 3/(2x) + 1? These are very different equations :) - Jan 9th 2013, 09:21 AMphyfreakRe: simple graphing in algebra
sorry, i meant:

y = (3/2)x + 1 - Jan 9th 2013, 09:36 AMMarkFLRe: simple graphing in algebra
We are given to graph:

$\displaystyle y=\frac{3}{2}x+1$

This line is in the so-called slope-intercept form $\displaystyle y=mx+b$, where $\displaystyle m$ is the slope and the*y*-intercept is $\displaystyle (0,b)$.

So, plot the*y*-intercept first...it is (0,1).

Now, since the slope is $\displaystyle m=\frac{3}{2}$, from the*y*-intercept you may move two units to the right and three units up to (2,4) and plot a point there. Now, extend a line through the two points and you will have graphed the equation.

Another method we be to write the equation in the two-intercept form $\displaystyle \frac{x}{a}+\frac{y}{b}=1$:

$\displaystyle \frac{x}{-\frac{2}{3}}+\frac{y}{1}=1$

Now, we can see we have the two intercepts:

$\displaystyle \left(-\frac{2}{3},0 \right),\,(0,1)$

Plot these points and extend a line through them. - Jan 9th 2013, 11:08 AMphyfreakRe: simple graphing in algebra
very useful.. thanks

im really dumb now i forgot math and i have to get at least 30% in a placement test for college, so im reviewing a lot now