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Thread: LiMiTs

  1. #1
    Member srirahulan's Avatar
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    Exclamation LiMiTs

    $\displaystyle \lim_{x\rightarrow 0}\frac{sin^2x-x^2cosx}{x^3tanx}$

    $\displaystyle \lim_{x\rightarrow \infty}\frac{2^{x+1}+3^{x+1}}{2^x+3^x}$

    In the second one how can i change the $\displaystyle x\rightarrow \infty$
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  2. #2
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    Re: LiMiTs

    Quote Originally Posted by srirahulan View Post
    $\displaystyle \lim_{x\rightarrow \infty}\frac{2^{x+1}+3^{x+1}}{2^x+3^x}$
    In the second one how can i change the $\displaystyle x\rightarrow \infty$

    The answer is that you should not.

    It is just $\displaystyle \frac{6\left(\frac{2}{3}\right)^x+3}\frac{\left( \frac{2}{ 3}\right)^x+1}$
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  3. #3
    Member srirahulan's Avatar
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    Re: LiMiTs

    What do you mean i can't understand?
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  4. #4
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    Re: LiMiTs

    Quote Originally Posted by srirahulan View Post
    What do you mean i can't understand?
    What do you mean?

    That is just basic algebra. Divide by $\displaystyle 3^x$.

    There is no reason to try limits if one can't do algebra.
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  5. #5
    Member srirahulan's Avatar
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    Re: LiMiTs

    Thank you.........
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