# LiMiTs

• Jan 9th 2013, 06:32 AM
srirahulan
LiMiTs
$\displaystyle \lim_{x\rightarrow 0}\frac{sin^2x-x^2cosx}{x^3tanx}$

$\displaystyle \lim_{x\rightarrow \infty}\frac{2^{x+1}+3^{x+1}}{2^x+3^x}$

In the second one how can i change the $\displaystyle x\rightarrow \infty$
• Jan 9th 2013, 06:47 AM
Plato
Re: LiMiTs
Quote:

Originally Posted by srirahulan
$\displaystyle \lim_{x\rightarrow \infty}\frac{2^{x+1}+3^{x+1}}{2^x+3^x}$
In the second one how can i change the $\displaystyle x\rightarrow \infty$

The answer is that you should not.

It is just $\displaystyle \frac{6\left(\frac{2}{3}\right)^x+3}\frac{\left( \frac{2}{ 3}\right)^x+1}$
• Jan 9th 2013, 07:04 AM
srirahulan
Re: LiMiTs
What do you mean i can't understand?
• Jan 9th 2013, 07:12 AM
Plato
Re: LiMiTs
Quote:

Originally Posted by srirahulan
What do you mean i can't understand?

What do you mean?

That is just basic algebra. Divide by $\displaystyle 3^x$.

There is no reason to try limits if one can't do algebra.
• Jan 9th 2013, 07:42 AM
srirahulan
Re: LiMiTs
Thank you.........