Let:
and use the given points to state:
The second equation tells you , and this along with the first and third equations will give you two equations and two unknowns.
Hi All,
I would really appreciate some help/hints for the following problem I am stuck on.
Determine the quadratic function whose graph is given:
The function has given points at (-1,5), (3,5), and y-intercept at (0,-1)
I know that the axis of symmetry (h) is at 1 because it is the mid-point between -1 and 3. If I plug that into the function a(x-h)^2 + k, I still have two unknowns, a and k
a(x-1)^2+k
Can someone please explain to me how to solve this. Thank you very much in advance.
Alex