• January 7th 2013, 07:47 AM
Please say me where I am wrong.... or show me how to continue to solve this equation...
Thanks
Attachment 26502
• January 7th 2013, 08:05 AM
jakncoke
is the comma supposed to be a dot in $2 lg^3 x - 1,5x$
• January 7th 2013, 08:12 AM
isn't it the same? you can write it like that: $\left( {2{{\lg }^3}x - {3 \over 2}x} \right) \cdot \lg x = {1 \over 2}$
• January 7th 2013, 02:56 PM
skeeter
Getting back to the original equation, because you have the unknown, x, as base and in the exponent, there is not going to be any "algebraic" method. You might, with a lot of algebraic manipulation, get this into a form in which you could apply "Lambert's W function" (defined as the inverse function to $f(x)= xe^x$) but I don't see any simple way to do that.