I only had to do problems 1, 2, and 5...The only one that i did not get was part c of number 5....
Hello, aikenfan!
This must be rationalized .. .$\displaystyle 5c)\;\;\frac{\sqrt{3}}{\sqrt{2}}$
Multiply top and bottom by $\displaystyle \sqrt{2}\!:\;\;\frac{\sqrt{2}}{\sqrt{2}}\cdot\frac {\sqrt{3}}{\sqrt{2}} \:=\:\frac{\sqrt{6}}{\sqrt{4}} \;=\;\frac{\sqrt{6}}{2}$