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Math Help - Radicals...Check work please

  1. #1
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    Radicals...Check work please

    I only had to do problems 1, 2, and 5...The only one that i did not get was part c of number 5....
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  2. #2
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    Hello, aikenfan!

    5c)\;\;\frac{\sqrt{3}}{\sqrt{2}}
    This must be rationalized .. .

    Multiply top and bottom by \sqrt{2}\!:\;\;\frac{\sqrt{2}}{\sqrt{2}}\cdot\frac  {\sqrt{3}}{\sqrt{2}} \:=\:\frac{\sqrt{6}}{\sqrt{4}} \;=\;\frac{\sqrt{6}}{2}

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  3. #3
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    Thank you! Do the others seem correct?...I was having a lot of trouble with this before...
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  4. #4
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    Hello, aikenfan!

    The others are correct . . . Good work!

    . . And thank you for showing your work.

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