Found this problem looking in my old textbook:
If Attachment 26388, find the numerical value of the ratio Attachment 26389.
I started cross multiplying & I got stuck quite easily. How do I finish this?
Use a common denominator.
I agree with your advice, but would I then solve for a/b?
thanks I remember attempting this problem a few years ago, didn't turn out well.
(4a-9b)/4a= (a-2b)/b Just cross multiply and we get
4ab – 9b^2 = 4a^2 – 8 ab
Or 4a^2 – 12 ab + 9 b^2 = 0
( 2a )^2 – 2 ( 2a) ( 3b) + ( 3b)^2 = 0
( 2a – 3b)^2 = 0
That gives a = 1.5 b