$\displaystyle 0 = \frac{2}{3} + 2C + D$

$\displaystyle 0 = 2 +6B +6C + 4D + 4E$

$\displaystyle 6 = 10 + 12B - 6C +10D -5E$

$\displaystyle 0 = \frac{1}{3} + B + D$

I dont know where to start, since the first and last equations dont have any similar terms, what strategy is there for this?