problem one: ax = bx +c the answer is: x = c/(a-b) problem two: ax - b = cx + d the answer is: x = (d+b)/(a-c) I'm pretty lost here, and would appreciate any help.
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$\displaystyle \displaystyle \begin{align*} a\,x &= b\,x + c \\ a\,x - b\,x &= c \\ x\left( a - b \right) &= c \\ x &= \frac{c}{a - b} \end{align*}$ Can you follow a similar process to solve the second one?
ax - b = cx + d ax = cx + (d + b) ax - cx = (d + b) x (a - c) = (d + b) x = (a - c)/(d + b) Thank you, it's clear to me now even if it doesn't seem so without the tex tags.
Originally Posted by sweezy ax - b = cx + d ax = cx + (d + b) ax - cx = (d + b) x (a - c) = (d + b) <--- up to this line evrything is fine, but then ..... x = (a - c)/(d + b) Thank you, it's clear to me now even if it doesn't seem so without the tex tags. x (a - c) = (d + b) ........ You now have to divide by (a - c) which yields: x = (d + b) / (a - c)
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