Thread: basic solving for x

problem one:
ax = bx +c
the answer is:
x = c/(a-b)

problem two:
ax - b = cx + d
the answer is:
x = (d+b)/(a-c)


I'm pretty lost here, and would appreciate any help.

Can you follow a similar process to solve the second one?

ax - b = cx + d
ax = cx + (d + b)
ax - cx = (d + b)
x (a - c) = (d + b)
x = (a - c)/(d + b)

Thank you, it's clear to me now even if it doesn't seem so without the tex tags.

Originally Posted by sweezy

ax - b = cx + d
ax = cx + (d + b)
ax - cx = (d + b)
x (a - c) = (d + b) <--- up to this line evrything is fine, but then .....
x = (a - c)/(d + b)

Thank you, it's clear to me now even if it doesn't seem so without the tex tags.

x (a - c) = (d + b) ........ You now have to divide by (a - c) which yields:

x = (d + b) / (a - c)