1. ## basic algebra

x-p/x+p = p+q/p-q

thnx

2. ## Re: basic algebra

Originally Posted by NormalKid
[SIZE=6]x-p/x+p = p+q/p-q

First of all, please use grouping symbols.

Is the problem $\displaystyle \frac{x-p}{x+p}=\frac{p+q}{p-q}~?$

The way you have posted it reads:
$\displaystyle x-\frac{x}{p}+p=p+\frac{q}{p}-q$.

Which is it?

3. ## Re: basic algebra

the first one
how do u do thaat?

4. ## Re: basic algebra

Hello, NormalKid!

What is the question?
I'll take a guess . . .

$\displaystyle \text{Solve for }x\!:\;\frac{x-p}{x+p} \:=\:\frac{p+q}{p-q}$

Cross-multiply: .$\displaystyle (x-p)(p-q) \:=\:(x+p)(p+q)$

.n. . . . . . . . $\displaystyle {\color{red}\rlap{//}}px - qx - p^2 + {\color{green}\rlap{//}}pq \:=\:{\color{red}\rlap{//}}px + qx + p^2 + {\color{green}\rlap{//}}pq$

n . . . . . . . . . . . . . . . . . . $\displaystyle 2qx \:=\:-2p^2$

. . . . . . . . . . . . . . . . . . . . . $\displaystyle x \:=\:-\frac{p^2}{q}$

5. ## Re: basic algebra

Originally Posted by Soroban
Hello, NormalKid!

What is the question?
I'll take a guess . . .

Cross-multiply: .$\displaystyle (x-p)(p-q) \:=\x+p)(p+q)$

.n. . . . . . . . $\displaystyle {\color{red}\rlap{//}}px - qx - p^2 + {\color{green}\rlap{//}}pq \:=\:{\color{red}\rlap{//}}px + qx + p^2 + {\color{green}\rlap{//}}pq$

n . . . . . . . . . . . . . . . . . . $\displaystyle 2qx \:=\:-2p^2$

. . . . . . . . . . . . . . . . . . . . . $\displaystyle x \:=\:-\frac{p^2}{q}$
good guessing Soroban sir.
so my guess was correct !
THANK YOU EVERYBODY. SP.THANKS TO YOU SIR.