x-p/x+p = p+q/p-q
sorry about the...inaccuracy.please solve this I tried this like 10 times already and i always get 2(xq+p^{2}) or something and I know its wrong. please help me
thnx
Hello, NormalKid!
What is the question?
I'll take a guess . . .
$\displaystyle \text{Solve for }x\!:\;\frac{x-p}{x+p} \:=\:\frac{p+q}{p-q}$
Cross-multiply: .$\displaystyle (x-p)(p-q) \:=\:(x+p)(p+q)$
.n. . . . . . . . $\displaystyle {\color{red}\rlap{//}}px - qx - p^2 + {\color{green}\rlap{//}}pq \:=\:{\color{red}\rlap{//}}px + qx + p^2 + {\color{green}\rlap{//}}pq$
n . . . . . . . . . . . . . . . . . . $\displaystyle 2qx \:=\:-2p^2$
. . . . . . . . . . . . . . . . . . . . . $\displaystyle x \:=\:-\frac{p^2}{q}$