# Pipes and reservoir...problem

• Dec 26th 2012, 05:58 AM
hisajesh
Pipes and reservoir...problem
3 pipes can fill a reservoir in 10, 15, 20 hours. If the three taps are opened one after the another in the given order, with a certain fixed time gap between them, the reservoir fills in 5 hours. Find the time gap.
• Dec 26th 2012, 06:09 AM
skeeter
Re: Pipes and reservoir...problem
Quote:

Originally Posted by hisajesh
3 pipes can fill a reservoir in 10, 15, 20 hours. If the three taps are opened one after the another in the given order, with a certain fixed time gap between them, the reservoir fills in 5 hours. Find the time gap.

you've posted a couple of these rate problems ... I set up the "keg" problem for you. what can you do with this one?
• Dec 26th 2012, 06:31 AM
HallsofIvy
Re: Pipes and reservoir...problem
In problems like this, where different things are combined, it is the rates that add. "3 pipes can fill a reservoir in 10, 15, 20 hours." so the rates at which the pipes fill the reservoir are 1/10, 1/15, and 1/20 "reservior per hour" respectively. Let the time gap you are looking for be "T" hours. Then you use the first pipe only for "T" hours, the first two pipes for an additional "T" hours, and all three for "5- 2T" hours. How much of reservoir will be filled in 5 hours? Set that equal to 1 and solve for T.