"n" is a specific integer value while you "a" varies from 1 up to n- 2 and so counts the number of terms.
That is, if n is, say 10, then 7, 9, 11, ..., 2n+ 1 is 7, 9, 11, 13, 15, 17, 19, 21 while a is 1, 2, 3, 5, 5, 7, 8.
I have the answer to this but I'm not sure that I entirely understand it.
Find the number of terms in the AP: 7 + 9 +...+ (2n+1)
My solution:
The ath term will be 2a + 5 so 2a + 5 = 2n + 1 therefore a = n - 2
This gives me the right answer but what I don't understand is what the difference between n and a is? Initially I thought that they were the same value but of course that is not possible. I would normally think of the 'ath term' as the 'nth term' so is (2n+1) just an expression that happens to use n as a variable just to be awkward?
I would really appreciate it if somebody could clarify this for me.
Merry Christmas!
"n" is a specific integer value while you "a" varies from 1 up to n- 2 and so counts the number of terms.
That is, if n is, say 10, then 7, 9, 11, ..., 2n+ 1 is 7, 9, 11, 13, 15, 17, 19, 21 while a is 1, 2, 3, 5, 5, 7, 8.
Ok well I normally think of the 'nth' term as the term that is found in a particular place in the sequence/series ie when n=10 the 10th term in the series is 25.
In this case is n not related to this and just a fixed value? Sorry but I'm still a bit confused...
I think that the confusion comes from the fact you are using in two different ways. Let's look at the OP.
You are to find "the number of terms" as a function of and that is not the same as the term.
Actually you did the problem correctly. There are terms in that A.P.
There are terms in .
Would it be more natural if the problem asked, "Find the number of terms in the AP: 7 + 9 +...+ (2 +1) "? Possibly, but this formulation is exactly equivalent to "Find the number of terms in the AP: 7 + 9 +...+ (2 +1)." Both variants say, "Fix some number and call it in the first variant and in the second variant. Consider the arithmetic progression 7 + 9 +...+ (2 +1) or, respectively, 7 + 9 +...+ (2 +1) and find the number of terms as a function of , or, respectively, ."
The variable does not have a monopoly on denoting the index of a sequence. Any variable can be used for this. Similarly, even in a text talking about a sequence of numbers, can denote many different things. In this case, it denotes some number such that is the last element of the sequence.
The AP is: 7,9,11,…… ( 2n+1)
Ok Let us presume that the AP has ‘m’ terms thus we have for the given AP
First term a1 = 7 common difference d = 2, and last term i.e., mth term = 2n + 1
But am = a1 + ( m-1) d
= 7 + ( m-1) x 2 = 7 + 2m – 2 = 2m + 5
It is given that the last term am = 2n + 1
Thus we have 2m + 5 = 2n + 1
That give m = n -2
Hence the AP has n-2 terms.