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Math Help - Laws of Logarithms

  1. #1
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    Laws of Logarithms

    In order to simplify the function ln(e^e^x) would I use the law ln(a^x) = x? This would give me e^x

    And for the function e^(ln(2x+1)) would I use the law e^ln(x) = x? This would give me 2x+1

    Sorry if the notation is confusing, I hope it makes sense, and thanks in advance.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Adrian View Post
    In order to simplify the function ln(e^e^x) would I use the law ln(a^x) = x? This would give me e^x
    the law is not \ln a^x = x it is \log_a a^x = x ...( \ln a^x = x \ln a ...which is a variation of another law)

    now, \ln \equiv \log_e

    so, \ln e^{e^x} = e^x as you said.

    And for the function e^(ln(2x+1)) would I use the law e^ln(x) = x? This would give me 2x+1
    correct
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