# Graphing

• Dec 19th 2012, 11:13 PM
Tutu
Graphing
Hi I'm not sure if this is the right forum to post a graphing question but I apologize if it is not..

The curve C has equation
$\displaystyle \frac{(x-2)(x-a)}\{(x-1)(x-3)}$ where a is not equal to 1,2 or 3.

I know how to do all the parts to this question except for one part, which is:

Sketch the graph of C for
a.) a>3
b.) 2<a<3

I am unsure how to do this part, for I am unable to find the value for a and thus the equation for C. Previously, one of parts to the question asked to find the set of values for which C has stationary points, and I got 1<a<3 but I don't see how this will help, after all it is not a definite single value of a but a range of values.

I know the axial intercepts for the graph and the asymptotes, and how the graph should look like, ( three parts, a concave down curve in the middle, and the other two curves to the left and right of the vertical asymptotes, bending away from these asymptotes since it the equation involves x^2. ) But I am not sure how to draw the graph, or is it that these information is sufficient?

Thank you!
• Dec 19th 2012, 11:17 PM
Tutu
Re: Graphing
Hi sorry, the (x-1)(x-3) is the denominator. Thank you so much!