# Thread: I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

1. ## I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

Hello, my name is Ameer, and I'm new here.

So basically I'm studying math for the Psychometric exam (an Israeli exam required for university), and I need help solving this:

(m+5)/(m-5)+(m+15)/(10-2m)=?

The following possibilities are given:

1. 1/2
2. 2
3. -1/2
4. -2

Which one is the right solution? And please explain to me how you got to the right solution.

Thanks a lot for the help.

EDIT: I'll be posting more questions on math throughout my studying period, so expect more from me, lol!

2. ## Re: I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

Lol it's ok I solved it. I assumed that m=0, thus the right answer is 1/2.

Thanks anyways.

3. ## Re: I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

Originally Posted by Ameer27
Hello, my name is Ameer, and I'm new here.

So basically I'm studying math for the Psychometric exam (an Israeli exam required for university), and I need help solving this:

(m+5)/(m-5)+(m+15)/(10-2m)=?
Note that you can factor a -2 out of the denominator of the second fraction, leaving -2(m- 5). And that means that you can get "common denominators" by multiplying the numerator and denominator of the first fraction by -2.:
-2(m+5)/(-2(m-5))+ (m+ 15)/(-2)(m- 5). Now the denominators are the same so you just need to add the numerators.

The following possibilities are given:

1. 1/2
2. 2
3. -1/2
4. -2

Which one is the right solution? And please explain to me how you got to the right solution.

Thanks a lot for the help.
The correct solution is NOT in that list! It is a function of m, not a constant.
EDIT: I'll be posting more questions on math throughout my studying period, so expect more from me, lol!
It was kind of a give away that they listed only constants!