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Math Help - I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

  1. #1
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    Question I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

    Hello, my name is Ameer, and I'm new here.

    So basically I'm studying math for the Psychometric exam (an Israeli exam required for university), and I need help solving this:

    (m+5)/(m-5)+(m+15)/(10-2m)=?

    The following possibilities are given:

    1. 1/2
    2. 2
    3. -1/2
    4. -2

    Which one is the right solution? And please explain to me how you got to the right solution.

    Thanks a lot for the help.

    EDIT: I'll be posting more questions on math throughout my studying period, so expect more from me, lol!
    Last edited by skeeter; December 14th 2012 at 12:08 PM.
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  2. #2
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    Re: I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

    Lol it's ok I solved it. I assumed that m=0, thus the right answer is 1/2.

    Thanks anyways.
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  3. #3
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    Re: I need help with solving this: (m+5)/(m-5)+(m+15)/(10-2m)=?

    Quote Originally Posted by Ameer27 View Post
    Hello, my name is Ameer, and I'm new here.

    So basically I'm studying math for the Psychometric exam (an Israeli exam required for university), and I need help solving this:

    (m+5)/(m-5)+(m+15)/(10-2m)=?
    Note that you can factor a -2 out of the denominator of the second fraction, leaving -2(m- 5). And that means that you can get "common denominators" by multiplying the numerator and denominator of the first fraction by -2.:
    -2(m+5)/(-2(m-5))+ (m+ 15)/(-2)(m- 5). Now the denominators are the same so you just need to add the numerators.

    The following possibilities are given:

    1. 1/2
    2. 2
    3. -1/2
    4. -2

    Which one is the right solution? And please explain to me how you got to the right solution.

    Thanks a lot for the help.
    The correct solution is NOT in that list! It is a function of m, not a constant.
    EDIT: I'll be posting more questions on math throughout my studying period, so expect more from me, lol!
    It was kind of a give away that they listed only constants!
    Last edited by HallsofIvy; December 14th 2012 at 02:49 PM.
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