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Math Help - how was this factored?

  1. #1
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    how was this factored?

    how was this factored?-picture-18.png

    I can't figure out how this is true. how was this factored?
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    Re: how was this factored?

    Quote Originally Posted by kingsolomonsgrave View Post
    Click image for larger version. 

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    I can't figure out how this is true. how was this factored?

    x^2-x-6=(x+2)(x-3).
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    Re: how was this factored?

    what happened to the x in the numerator?
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    Re: how was this factored?

    In order to subtract the two functions they must first have the same denominator.
    If you multiply 4/(x-3) by x+2 you should get (4x+8) / (x^2-x-6)'
    Then multiply 1/(x+2) by x-3 and your answer should be (x-3) / (x^2-6).

    You then combine the numerator by like terms all over the denominator. It should look like (4x-x+8-(-3) / (x^2-x-6)
    4x - x = 3x and 8 - (-3) = 11 (Using skip change change)
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    Re: how was this factored?

    Quote Originally Posted by kingsolomonsgrave View Post
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    I can't figure out how this is true. how was this factored?
    Partial-Fraction Decomposition: General Techniques
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