Dahlai walks from home to school at 2km/h. After school she jogs back home at 6km/h and saves 15 mins. How far away is her house from school? I don't even know how to approach this, all help is appreciated.

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- Dec 13th 2012, 07:09 AMxXplosionZzHelp with a distance problem
Dahlai walks from home to school at 2km/h. After school she jogs back home at 6km/h and saves 15 mins. How far away is her house from school? I don't even know how to approach this, all help is appreciated.

- Dec 13th 2012, 07:15 AMBeanRe: Help with a distance problem
Remember that distance equals rate*time. She is traveling the same distance going to school as coming home.

$\displaystyle 2x=6(x-\frac{1}{4})$

Can you take it from there? - Dec 13th 2012, 09:52 AMSorobanRe: Help with a distance problem
Hello, xXplosionZz!

Recall the formula: .$\displaystyle d \:=\:rt \quad\Rightarrow\quad t \:=\:\tfrac{d}{r}$

Quote:

Dahlai walks from home to school at 2km/hr.

After school she jogs back home at 6km/hr and saves 15 mins.

How far away is her house from school?

She walks $\displaystyle x$ km at 2 km/hr.

. . This takes $\displaystyle \frac{x}{2}$ hours.

She jogs $\displaystyle x$ km at 6 km/hr.

. . This takes $\displaystyle \frac{x}{6}$ hours.

Her jogging time is $\displaystyle \tfrac{1}{4}$ hour less than her walking time.

. . The equation is: .$\displaystyle \frac{x}{6} \:=\:\frac{x}{2} - \frac{1}{4}$

Got it?

- Dec 13th 2012, 06:35 PMxXplosionZzRe: Help with a distance problem
Sorta got it, thanks. Do you have any other questions like this to practise?