Am i doing this right?

(5x+10)^2 = 40
(5x+10)(5x+10)= 40
25x^2 + 100x + 100 = 40
25x^2 + 100x + 60 = 0

once i get that last equation i do this

(-100 (+/-) sq(10000-6000))/50

then i simply this far

(-80 sq(10))50 and (-120 sq(10))/50

but the multiple choice answers dont look like what i got :/

$\displaystyle (5x+10)^2 = 40$

$\displaystyle 5x+10 = \pm \sqrt{40}$

$\displaystyle 5x+10 = \pm 2\sqrt{10}$

$\displaystyle 5x = -10 \pm 2\sqrt{10}$

$\displaystyle x = -2 \pm \frac{2\sqrt{10}}{5}$

Originally Posted by DeltaHax
Am i doing this right?

(5x+10)^2 = 40
(5x+10)(5x+10)= 40
25x^2 + 100x + 100 = 40
25x^2 + 100x + 60 = 0

once i get that last equation i do this

(-100 (+/-) sq(10000-6000))/50

then i simply this far

(-80 sq(10))50 and (-120 sq(10))/50

but the multiple choice answers dont look like what i got :/
You are correct up to \displaystyle \displaystyle \begin{align*} \frac{-100 \pm \sqrt{10 \, 000 - 6000}}{50} \end{align*}, which then simplifies to

\displaystyle \displaystyle \begin{align*} \frac{-100 \pm \sqrt{4000}}{50} &= \frac{-100 \pm 20\sqrt{10}}{50} \\ &= \frac{-10 \pm 2\sqrt{10}}{5} \end{align*}

But Skeeter's method is better.