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Math Help - Trouble with a Logarithm problem

  1. #1
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    Trouble with a Logarithm problem

    This is the problem: log4-3log(y+2) where the base is 6

    Im stuck at this part im not sure how to solve it:
    log4-3log(y+2)= log4 over 3log(y+2)

    i know (y+2)^3 = 3log(y+2)
    i know log4 = 6^x=4

    if im wrong please tell me. please show me how to solve with problem step by step with explanations.
    THANKS
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  2. #2
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    Re: Trouble with a Logarithm problem

    I got this answer, is it correct?

    log 4 over (y+2) with a base of 6
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  3. #3
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    Re: Trouble with a Logarithm problem

    \log_6{4} - 3\log_6(y+2) = \log_6\left[\frac{4}{(y+2)^3} \right]
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