Trouble with a Logarithm problem

This is the problem: log4-3log(y+2) where the base is 6

Im stuck at this part im not sure how to solve it:

log4-3log(y+2)= log4 over 3log(y+2)

i know (y+2)^3 = 3log(y+2)

i know log4 = 6^x=4

if im wrong please tell me. please show me how to solve with problem step by step with explanations.

THANKS(Rock)

Re: Trouble with a Logarithm problem

I got this answer, is it correct?

log 4 over (y+2) with a base of 6

Re: Trouble with a Logarithm problem

$\displaystyle \log_6{4} - 3\log_6(y+2) = \log_6\left[\frac{4}{(y+2)^3} \right]$