Hi! Great site. How would I solve for n if n is an exponent?
2n=128
this is an Elementary/Middle school poster, he/she probably does not know how to use logs yet.
note that the prime factorization of 128 will show that:
128 = 2*2*2*2*2*2*2 = 2^7
so 2^n = 2^7
since the bases are the same, the powers must be the same, thus we can equate them. and we get:
n = 7
Some of the helpers/masters here sometimes think the askers are as good as they are. But some helpers too take the pains to explain to the most Math-challenged askers even if those in the first group might snicker at it.
Helping those who seek help and solving the Problems only are two different things. It is more difficult to explain as detailed as possible. Solving is easy.
Don't be disappointed in this your first try. Ask some more, anytime.
i see nothing rude about my response. i did not just say "i told you" i proceeded to explain further. furthermore, i gave a simpler solution than ticbol, again with explanation. the helpers here don't want to just give out solutions, they want the student to actually learn, so the often give hints and wait for the poster to try them. you showed no indication that you tried the hints that were given, which was the reason for my response. just asking for solutions won't help you. and as for thinking that other users are as "good as i am," i am guilty of no such thing, and frankly, i do not think any other helper here is, maybe other users, but no helper believes that.
I was just kidding. Hey Jamaica is very nice. Ya Mon.
This is funny though:
The Following 2 Users Say Thank You to Jhevon For This Useful Post: SnipedYou (Yesterday), topsquark (Yesterday)
Heheh. If I say thank you do I get a cookie? Heheh.
Thank you. Sorry for misunderstanding. I'm off to have a red stripe.