Reduce to lowest terms:

I don't see how this can be factored to be reduced. Thanks.

The answer is

Printable View

- Dec 10th 2012, 09:58 PMKhanDisciplePolynomial Reduction Help
Reduce to lowest terms:

I don't see how this can be factored to be reduced. Thanks.

The answer is - Dec 10th 2012, 11:30 PMgrillageRe: Polynomial Reduction Help
Just to be sure, is that really for the second term in the denominator?

- Dec 11th 2012, 02:15 AMMarkFLRe: Polynomial Reduction Help
For the numerator:

You could use the rational roots theorem, which states that if the given polynomial has a rational root, it will come from the list . We can see that cannot work, hence we find:

So, we know is a factor of . Use of division finds:

Now, for the denominator, we should recognize the binomial coefficients arising from the cube of a binomial, i.e.:

and so we may state:

- Dec 11th 2012, 06:27 AMKhanDiscipleRe: Polynomial Reduction Help
grillage - you are correct it is . Thanks for the help markFL2, I didn't know about the rational roots theorem, that will make working with polynomials a whole lot easier.