I would write:
Now, apply the properties of logs and you should find the only remaining log is the one for which you are given an approximation.
Given that logbase6(2)=0.387, Determine the value of logbase6(9)...
this is where i got....
2logbase6(3)/logbase6(3)+logbase6(2)
our teacher said this should be easy but for some reason i am stuck
plzzhelp me solve