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Math Help - a easy log question...need solved....stuck

  1. #1
    Newbie
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    kanaida
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    a easy log question...need solved....stuck

    Given that logbase6(2)=0.387, Determine the value of logbase6(9)...

    this is where i got....
    2logbase6(3)/logbase6(3)+logbase6(2)

    our teacher said this should be easy but for some reason i am stuck
    plzzhelp me solve
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  2. #2
    MHF Contributor MarkFL's Avatar
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    St. Augustine, FL.
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    Re: a easy log question...need solved....stuck

    I would write:

    \log_6(9)=\log_6\left(\frac{36}{4} \right)

    Now, apply the properties of logs and you should find the only remaining log is the one for which you are given an approximation.
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