# a easy log question...need solved....stuck

• Dec 10th 2012, 08:09 PM
koolaid123
a easy log question...need solved....stuck
Given that logbase6(2)=0.387, Determine the value of logbase6(9)...

this is where i got....
2logbase6(3)/logbase6(3)+logbase6(2)

our teacher said this should be easy but for some reason i am stuck
plzzhelp me solve
• Dec 10th 2012, 08:50 PM
MarkFL
Re: a easy log question...need solved....stuck
I would write:

$\log_6(9)=\log_6\left(\frac{36}{4} \right)$

Now, apply the properties of logs and you should find the only remaining log is the one for which you are given an approximation.