Given that logbase6(2)=0.387, Determine the value of logbase6(9)...

this is where i got....

2logbase6(3)/logbase6(3)+logbase6(2)

our teacher said this should be easy but for some reason i am stuck

plzzhelp me solve

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- Dec 10th 2012, 07:09 PMkoolaid123a easy log question...need solved....stuck
Given that logbase6(2)=0.387, Determine the value of logbase6(9)...

this is where i got....

2logbase6(3)/logbase6(3)+logbase6(2)

our teacher said this should be easy but for some reason i am stuck

plzzhelp me solve - Dec 10th 2012, 07:50 PMMarkFLRe: a easy log question...need solved....stuck
I would write:

$\displaystyle \log_6(9)=\log_6\left(\frac{36}{4} \right)$

Now, apply the properties of logs and you should find the only remaining log is the one for which you are given an approximation.