Need to solve for q.

f=.2083(100/c)^1.852*q^1.852/dh^4.8655*5280/100

Printable View

- Dec 10th 2012, 07:34 AMblsamuelsNeed help solving equation
Need to solve for q.

f=.2083(100/c)^1.852*q^1.852/dh^4.8655*5280/100 - Dec 10th 2012, 09:24 AMebainesRe: Need help solving equation
This is an equation of the form:

$\displaystyle f = \frac {Aq^{1.852}} B$

where A and B are constants: $\displaystyle A = 0.2083 (\frac {100} C ) ^{1.852}$ and $\displaystyle B=dh^{4.8655} (\frac {5280} {100})$. So you can rearrange as follows:

$\displaystyle q^{1.852} = \frac {fB} A$

$\displaystyle 1.852 \log(q) = \log ( \frac {fB} A )$

$\displaystyle \log (q) = \frac 1 {1.852} \log ( \frac {fB} A ) $

$\displaystyle q = e^{ [ \frac 1 {1.852} \log(fB/A) ]} = (\frac {fB} A )^\frac 1 {1.852}$