Need help solving equation

Quote:

Originally Posted by blsamuels

Need to solve for q.

f=.2083(100/c)^1.852*q^1.852/dh^4.8655*5280/100

This is an equation of the form:
$f = \frac {Aq^{1.852}} B$

where A and B are constants: $A = 0.2083 (\frac {100} C ) ^{1.852}$ and $B=dh^{4.8655} (\frac {5280} {100})$ . So you can rearrange as follows:

$q^{1.852} = \frac {fB} A$

$1.852 \log(q) = \log ( \frac {fB} A )$

$\log (q) = \frac 1 {1.852} \log ( \frac {fB} A )$

$q = e^{ [ \frac 1 {1.852} \log(fB/A) ]} = (\frac {fB} A )^\frac 1 {1.852}$