this system of equations has no solution ... think about why.5a = 5 - b
5a = 3 - b
5a = 5 - b
5a = 3 - b
I got the solution set to be 1/2, 5/2
i used substitution for substituting a into b of the second equation, just like they were x's and y's just used a's and b's there is no difference correct?
a = 1- b/5 from top equation.
then 5(1-b/5) = 3 - b
==5/2
then for 1/2 I substituted the b= 5/2 back into one of the original equations.
Does this look correct? Thanks alot.