Thread: the measure of the width of the property

Problem:

A man is planning a fence the front part of his property with posts 2m apart. Short
of money he decides to make the posts 3m apart and uses 3 posts less. How wide is the property?

can anybody help me understand this problem please....


how is the problem above be represented by variables and into equation.
thanks

Suppose he initially had n posts. Assuming he had one post at each end, there area n-1 intervals between posts and the width of the property is 2(n-1). If he uses "3 posts less", then he uses n- 3 posts, n- 3- 1= n- 4 intervals between them and so the width of the property is 3(n- 4). Since both 2(n- 1) and 3(n- 4) give the width of the property, set them equal and solve that equation for n. Put that vaue of n back into either formula to get the width of the property.