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Math Help - tugboat problem, check please.

  1. #1
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    tugboat problem, check please.

    R = rate of boat no current
    C = rate of current

    120 = 20(R-C)
    120 = 5(R+C)

    6 = (R-C)
    24 = (R+C)

    30 = +2R
    15 = R

    24-15 = -15 +15+C
    9 = C

    speed of tugboat is 15 mph, and the current is 9 mph.
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  2. #2
    MHF Contributor

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    Re: tugboat problem, check please.

    It would help if you told us what the problem itself says! Are you saying that the boat goes upstream 120 miles in 20 hours and goes downstream 120 miles in 5 hours?

    It should be easy for you to check it yourself. If the boat has a normal speed of 15 mph and the current is 9 mph, the actual speed of the boat upstream, relative to the shore, is 15- 9= 6 mph. In 20 hours, the boat will have gone 6(20)= 120 miles. Downstream, the actual speed, relative to the shore, is 15+9= 24 mph. In 5 hours the boat will have gone 5(24)= 120 mi. Looks good.
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  3. #3
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    Re: tugboat problem, check please.

    If i was cgoing to get in trouble for asking for help, i probably wouldn't have asked, lol!
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  4. #4
    Forum Admin topsquark's Avatar
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    Re: tugboat problem, check please.

    Quote Originally Posted by rcmango View Post
    If i was cgoing to get in trouble for asking for help, i probably wouldn't have asked, lol!
    The problem was not in asking for help, but not actually posting a question. For instance you found values for R and C. They mean nothing on their own. What is the actual problem statement for this question?

    Your post is a mystery. If you want help you're going to have to give more information.

    -Dan
    Last edited by topsquark; December 9th 2012 at 01:47 PM.
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