The tens digit of a number is 3 less than the units digit. If the number is divided

by the sum of the digits. The quotient is 4 and the remainder is 3. What is

he original number?

attempt:

let : x be unit digit

x - 3 be the tens digit

10(x-3) + x be the number

solve: [10(x-3) + x] / (x-3)+x = 4 + 3

please do check my representations and equation... and please correct my work..

thanks a lot

can anybody help me in representing the unknown please.