Thread: digits problem

The tens digit of a number is 3 less than the units digit. If the number is divided
by the sum of the digits. The quotient is 4 and the remainder is 3. What is
he original number?





attempt:

let : x be unit digit
x - 3 be the tens digit
10(x-3) + x be the number

solve: [10(x-3) + x] / (x-3)+x = 4 + 3

please do check my representations and equation... and please correct my work..


thanks a lot


can anybody help me in representing the unknown please.

Hello, rcs!

The tens digit of a number is 3 less than the units digit.
If the number is divided by the sum of the digits, the quotient is 4 and the remainder is 3.
What is the original number?

Let = units digit.
Let = tens digit.

The original number is: .
. . where: .[1]

Then: . .[2]

Subtract [1] from [2]: .

Substitute into [1]: .


The original number is