# Math Help - Quadratic formula

I need help getting the variable b by itself

this is what i have so far but need help finishing it. If you could show step by step instructions that'd be great.
(2a)(2a)
2ax=-b +/- sqrt(b^2-4ac)
+b +b
(2ax+b)^2= +/-sqrt( b^2-4ac)^2
(2ax+b)^2= b^2-4ac

If you are trying to take the quadratic formula and solve for $b$, it will be far simpler to take the quadratic from which the formula is derived, and solve that for $b$:

$ax^2+bx+c=0$

$bx=-(ax^2+c)$

$b=-\frac{ax^2+c}{x}$

I know t would be easier to do it that way but the question asks to go from the formula i posted but thanks!

Well, we can begin with the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$2ax=-b\pm\sqrt{b^2-4ac}$

$2ax+b=\pm\sqrt{b^2-4ac}$

$4a^2x^2+4abx+b^2=b^2-4ac$

$4a^2x^2+4abx+4ac=0$

With $a\ne0$ we have:

$ax^2+bx+c=0$