If I'm doing it wrong, where am I doing it wrong?
Here is my work
f(3) = 10 ; f(9) = 40
10a^6 = 40
a^6 = 4
a = 4^(1/6)
a = 1.25992105
10 = c(1.25992105)^3
1.25992105^3 ≈ 2
10/2 = C
5 = C
f(x) = 2(4)^x
is this the correct equation?
If I'm doing it wrong, where am I doing it wrong?
Here is my work
f(3) = 10 ; f(9) = 40
10a^6 = 40
a^6 = 4
a = 4^(1/6)
a = 1.25992105
10 = c(1.25992105)^3
1.25992105^3 ≈ 2
10/2 = C
5 = C
f(x) = 2(4)^x
is this the correct equation?
That is an oddly worded question.
So you want $\displaystyle f(x)=ca^x$ so $\displaystyle 10=ca^3~\&~40=ca^9~.$
From which we can see that $\displaystyle \frac{10}{a^3}=\frac{40}{a^9}$
So $\displaystyle a^6=4$ or $\displaystyle a=\sqrt[6]{4}$.
Can you find $\displaystyle c~?$