Thread: A simple one: (N+6)/53 = 0 I need to figure out what N needs to be

As the title says... trying to find N.

(N+6)/53 = 0

Thanks in advance!!

-Jeff

N = -6

Originally Posted by jeffs24

As the title says... trying to find N.
(N+6)/53 = 0

What makes

N cannot be a negative number

wow... I didnt even notice my own typo till just now...

correction:

(N+6)/53 = 1

Sorry!!!!

Ok so you will have 53=N+6 and what does N equal from that simple equation??

Im not at all asking this right....

(N+6)/53 = "the lowest possible whole number"

man its been a long day.

Multiply both sides by 53, then subtract 6 from both sides to solve for N.

look at what i said 53=n+6 and that gives you n=53-6 looks simply to me doesn't it?

You all answered perfect. Thank you.

To add another loop.... N also has to be divisible by either 53 or 60.

Originally Posted by jeffs24

Im not at all asking this right....

(N+6)/53 = "the lowest possible whole number"

man its been a long day.

It depends on how the whole numbers are defined. I was taught that they are {0,1,2,3,...}, but in some contexts they are synonymous with the natural numbers {1,2,3,...}.

In a mathematical definition whole numbers are 0,1,2...

Originally Posted by jeffs24

You all answered perfect. Thank you.

To add another loop.... N also has to be divisible by either 53 or 60.

Please post the entire problem from the start. Also, proof your post by clicking on the Go Advanced button, then click submit.