(x-2)^7 + 7x(x-2)^6 = 0 The answer is x = (1/4), but I don't know how to calculate this. Thanks.
Follow Math Help Forum on Facebook and Google+
(x-2)^6{x-2+7x} = 0 (x-2)^6{8x-2}=0 x-2 = 0 or 8x-2 = 0 x = 2 or 8x = 2 x = 2/8 = 1/4
View Tag Cloud