Solve: $\displaystyle 2^{x^{2}-6x+3}+6^{x^{2}-3x+1}\geq 3^{2x^{2}-6x+3}$
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It is not true for all x. x=3, 2^(9-18+3) = 2^(-6) 6^(9-9+1) = 6 2^(-6) + 6 is less than 3^(18-18+3) = 27
for x=1 =>5/12 > 4/12
Originally Posted by coolge It is not true for all x. x=3, 2^(9-18+3) = 2^(-6) 6^(9-9+1) = 6 2^(-6) + 6 is less than 3^(18-18+3) = 27 Yes, that's why metalari said "solve". For what values of x is it true?
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