Can anybody help me on this... What is the vertex of the graph y = 2 – | 2x – 3| ? how is it possible to be solve? Thanks
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You want to write it in the form: $\displaystyle y=a|x-h|+k$, where $\displaystyle a\ne0$ is a constant. Then, the point $\displaystyle (h,k)$ is the vertex.
Originally Posted by MarkFL2 You want to write it in the form: $\displaystyle y=a|x-h|+k$, where $\displaystyle a\ne0$ is a constant. Then, the point $\displaystyle (h,k)$ is the vertex. do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir?
Originally Posted by rcs What is the vertex of the graph y = 2 – | 2x – 3| ? I assume that by vertex yiou mean the 'sharp' point on the graph. That would be the maximum which occurs if $\displaystyle |2x-3|=0$. Draw the graph! You will see why.
Originally Posted by rcs do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir? No, I mean write it as $\displaystyle y=-2\left|x-\frac{3}{2} \right|+2$
How did you get y = -2 |x - 3/2| + 2 ... When the original was y = 2 - |2x-3| sir?
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