# solving vertex of absolute value

• Dec 1st 2012, 02:29 AM
rcs
solving vertex of absolute value
Can anybody help me on this...

What is the vertex of the graph y = 2 – | 2x – 3| ?

how is it possible to be solve?

Thanks
• Dec 1st 2012, 02:34 AM
MarkFL
Re: solving vertex of absolute value
You want to write it in the form:

$y=a|x-h|+k$, where $a\ne0$ is a constant.

Then, the point $(h,k)$ is the vertex.
• Dec 1st 2012, 03:46 AM
rcs
Re: solving vertex of absolute value
Quote:

Originally Posted by MarkFL2
You want to write it in the form:

$y=a|x-h|+k$, where $a\ne0$ is a constant.

Then, the point $(h,k)$ is the vertex.

do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir?
• Dec 1st 2012, 04:10 AM
Plato
Re: solving vertex of absolute value
Quote:

Originally Posted by rcs
What is the vertex of the graph y = 2 – | 2x – 3| ?

I assume that by vertex yiou mean the 'sharp' point on the graph.

That would be the maximum which occurs if $|2x-3|=0$.

Draw the graph! You will see why.
• Dec 1st 2012, 08:58 AM
MarkFL
Re: solving vertex of absolute value
Quote:

Originally Posted by rcs
do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir?

No, I mean write it as $y=-2\left|x-\frac{3}{2} \right|+2$
• Dec 3rd 2012, 07:32 PM
rcs
Re: solving vertex of absolute value
How did you get y = -2 |x - 3/2| + 2 ... When the original was y = 2 - |2x-3| sir?