solving vertex of absolute value

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December 1st 2012, 02:29 AM
rcs

solving vertex of absolute value

Can anybody help me on this...

What is the vertex of the graph y = 2 – | 2x – 3| ?

how is it possible to be solve?

Thanks
December 1st 2012, 02:34 AM
MarkFL

Re: solving vertex of absolute value

You want to write it in the form:

$y=a|x-h|+k$ , where $a\ne0$ is a constant.

Then, the point $(h,k)$ is the vertex.
December 1st 2012, 03:46 AM
rcs

Re: solving vertex of absolute value

Quote:

Originally Posted by MarkFL2

You want to write it in the form:

$y=a|x-h|+k$ , where $a\ne0$ is a constant.

Then, the point $(h,k)$ is the vertex.

do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir?
December 1st 2012, 04:10 AM
Plato

Re: solving vertex of absolute value

Quote:

Originally Posted by rcs

What is the vertex of the graph y = 2 – | 2x – 3| ?

I assume that by vertex yiou mean the 'sharp' point on the graph.

That would be the maximum which occurs if $|2x-3|=0$ .

Draw the graph! You will see why.
December 1st 2012, 08:58 AM
MarkFL

Re: solving vertex of absolute value

Quote:

Originally Posted by rcs

do you mean that y = 2 – | 2x – 3| can be y = – | 2x – 3| + 2,,, and so the h = 3 and k = - 2 ? it this correct sir?

No, I mean write it as $y=-2\left|x-\frac{3}{2} \right|+2$
December 3rd 2012, 07:32 PM
rcs

Re: solving vertex of absolute value

How did you get y = -2 |x - 3/2| + 2 ... When the original was y = 2 - |2x-3| sir?

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