The length of a rectangle is 10 feet less than twice the width. If the area of the rectangle is 168 square feet, find the dimensions of the rectangle?
Hello,Originally Posted by wild_flowr69
let x be the width of the rectangle. Then the length ist 2x-10. The dimension of the rectangle is x(2x-10)=168. You'll get:
$\displaystyle 2x^2-10x-168=0$
Solve this equation for x (I'm quite sure that you know to solve a quadratic equation) and you'll get x=12 or x=-7. The last solution isn't very probable at a rectangle.
Greetings
EB