# Rectangle

• Mar 5th 2006, 08:09 AM
wild_flowr69
Rectangle
The length of a rectangle is 10 feet less than twice the width. If the area of the rectangle is 168 square feet, find the dimensions of the rectangle?
• Mar 5th 2006, 08:26 AM
earboth
Quote:

Originally Posted by wild_flowr69
The length of a rectangle is 10 feet less than twice the width. If the area of the rectangle is 168 square feet, find the dimensions of the rectangle?

Hello,

let x be the width of the rectangle. Then the length ist 2x-10. The dimension of the rectangle is x(2x-10)=168. You'll get:
$2x^2-10x-168=0$
Solve this equation for x (I'm quite sure that you know to solve a quadratic equation) and you'll get x=12 or x=-7. The last solution isn't very probable at a rectangle.

Greetings

EB