The length of a rectangle is 10 feet less than twice the width. If the area of the rectangle is 168 square feet, find the dimensions of the rectangle?

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- Mar 5th 2006, 08:09 AMwild_flowr69Rectangle
The length of a rectangle is 10 feet less than twice the width. If the area of the rectangle is 168 square feet, find the dimensions of the rectangle?

- Mar 5th 2006, 08:26 AMearbothQuote:

Originally Posted by**wild_flowr69**

let x be the width of the rectangle. Then the length ist 2x-10. The dimension of the rectangle is x(2x-10)=168. You'll get:

$\displaystyle 2x^2-10x-168=0$

Solve this equation for x (I'm quite sure that you know to solve a quadratic equation) and you'll get x=12 or x=-7. The last solution isn't very probable at a rectangle.

Greetings

EB