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Math Help - Radicals - Division

  1. #1
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    Radicals - Division

    the question is 4/(4√64m4n2)
    the given answer is
    (4√4n2) / 2mn

    but I get 4(4√n2)/ 2mn

    4√ = root with 'index=4'

    *the index 4 root is for the all
    -( 64m4n2)
    -(4n2)
    -(n2)

    I'm not good at writing mathematics symbols sorry. help please SOS
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  2. #2
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    Re: Radicals - Division

    Quote Originally Posted by edmundyong View Post
    the question is 4/(4√64m4n2)
    the given answer is
    (4√4n2) / 2mn

    but I get 4(4√n2)/ 2mn

    4√ = root with 'index=4'

    *the index 4 root is for the all
    -( 64m4n2)
    -(4n2)
    -(n2)

    I'm not good at writing mathematics symbols sorry. help please SOS
    Hang on, is it \displaystyle \begin{align*} \frac{4}{\sqrt[4]{64m^4n^2}} \end{align*}?
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    Re: Radicals - Division

    yes I dunno how to type the 'root' like that
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    Re: Radicals - Division

    the fourth-root of (64m^4n^2) = 2m fourth-root(2^2 n^2) = 2m sqrt(2n). Then multipy and divide Nr and Dr by sqrt(2n) you will get the answer.
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    Re: Radicals - Division

    so you basically what you do is reduce the 4th-root(22n2 ) into sqrt(2n) by diving all by 2?
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    Re: Radicals - Division

    Quote Originally Posted by coolge View Post
    the fourth-root of (64m^4n^2) = 2m fourth-root(2^2 n^2) = 2m sqrt(2n).....
    so basically what you do is reduce the 4th-root(22n2 ) into sqrt(2n) by diving all by 2?
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    Re: Radicals - Division

    Quote Originally Posted by edmundyong View Post
    so basically what you do is reduce the 4th-root(22n2 ) into sqrt(2n) by diving all by 2?
    No, you take everything to the power of 1/4.
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    Re: Radicals - Division

    Quote Originally Posted by edmundyong View Post
    the question is 4/(4√64m4n2)
    the given answer is
    (4√4n2) / 2mn
    I'm not good at writing mathematics symbols sorry. help please SOS
    But you can learn to do the mathematical symbols.

    [tex]\frac{4}{\sqrt[4]{64m^4n^2}} [/tex] gives  \frac{4}{\sqrt[4]{64m^4n^2}}
    Click on the “go advanced” tab. On the toolbar you will see \boxed{\Sigma} clicking on that give the LaTeX wraps, [tex] [/tex]. The code goes between them.
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  9. #9
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    Re: Radicals - Division

    Quote Originally Posted by Prove It View Post
    No, you take everything to the power of 1/4.
    ok
    so it'll be 4/2m sqrt(2n)
    and mutiply all by sqrt(2n)
    1 question
    - is sqrt(2n) x sqrt(2n) = 2n?

    if yes then...the wouldn't the Nr become
    4 [sqrt(2n)] / 2m(2n)
    =4 [sqrt(2n) / 4mn
    ???
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