Solve the equation: Correct Answer: -6+7^(1/2) can someone explain how I would obtain the answer above? I know how to actually solve for x numerically, but I don't know how to get -6+7^(1/2)
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Start by simplifying the left hand side using the law of logarithms: log(x) + log(y) = log(xy)
I get x^2+12x+29=0 but how to factor that since 29 is prime?
Use the quadratic formula
Just as a reminder: $\displaystyle x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$
Originally Posted by kingsolomonsgrave I get x^2+12x+29=0 but how to factor that since 29 is prime? complete the square ... $\displaystyle x^2+12x = -29$ $\displaystyle x^2 + 12x + 36 = 36-29$ $\displaystyle (x + 6)^2 = 7$ $\displaystyle x+6 = \pm \sqrt{7}$ $\displaystyle x = -6 \pm \sqrt{7}$ since $\displaystyle x > -4$ ... $\displaystyle x = -6 + \sqrt{7}$
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