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Thread: Checking my answer

  1. November 24th 2012, 11:52 PM #1
    aroe
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    Checking my answer

    Sqrt(x)=-x

    x=0

    Right? It can't be positive or negative so it has to be 0.
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  2. November 24th 2012, 11:53 PM #2
    jakncoke
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    Re: Checking my answer

    looks good.
    Thanks from aroe
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  3. November 24th 2012, 11:59 PM #3
    MarkFL
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    Re: Checking my answer

    You could arrange as:

    x+\sqrt{x}=0

    \sqrt{x}(\sqrt{x}+1)=0

    Since 0\le\sqrt{x} we must have:

    \sqrt{x}=0

    x=0
    Thanks from aroe
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