Checking my answer

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Nov 24th 2012, 11:52 PM
aroe

Checking my answer

Sqrt(x)=-x

x=0

Right? It can't be positive or negative so it has to be 0.
Nov 24th 2012, 11:53 PM
jakncoke

Re: Checking my answer

looks good.
Nov 24th 2012, 11:59 PM
MarkFL

Re: Checking my answer

You could arrange as:

$x+\sqrt{x}=0$

$\sqrt{x}(\sqrt{x}+1)=0$

Since $0\le\sqrt{x}$ we must have:

$\sqrt{x}=0$

$x=0$

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