• November 24th 2012, 11:52 PM
aroe
Sqrt(x)=-x

x=0

Right? It can't be positive or negative so it has to be 0.
• November 24th 2012, 11:53 PM
jakncoke
looks good.
• November 24th 2012, 11:59 PM
MarkFL
$x+\sqrt{x}=0$
$\sqrt{x}(\sqrt{x}+1)=0$
Since $0\le\sqrt{x}$ we must have:
$\sqrt{x}=0$
$x=0$