# Checking my answer

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• Nov 25th 2012, 12:52 AM
aroe
Checking my answer
Sqrt(x)=-x

x=0

Right? It can't be positive or negative so it has to be 0.
• Nov 25th 2012, 12:53 AM
jakncoke
Re: Checking my answer
looks good.
• Nov 25th 2012, 12:59 AM
MarkFL
Re: Checking my answer
You could arrange as:

$x+\sqrt{x}=0$

$\sqrt{x}(\sqrt{x}+1)=0$

Since $0\le\sqrt{x}$ we must have:

$\sqrt{x}=0$

$x=0$