How to.solve log3(logx(4))=logx1? Thank you in advance!
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I assume you mean: $\displaystyle \log_3(\log_x(4))=\log_x(1)$ If so, what is $\displaystyle \log_a(1)$ for any valid base $\displaystyle a$?
0! I missed out on that! Thank you very very much!!
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