I forgot how to solve y^2(5-2y), to.give my answer in surd form. I thought to use -b+/-sqrt(b^2-4ac)/2a but I got an imaginary number and I don't think I can use completing the square method either..please help thanks a lot!
What do you mean by "solved?" $\displaystyle y^2(5 - 2y)$ is not an equation.
Taking a leap of faith I'm going to assume that you mean to solve
$\displaystyle y^2(5 - 2y) = 0$
In this case we know that $\displaystyle y^2 = 0$ or $\displaystyle 5 - 2y = 0$
Now go from there.
-Dan